
Patrick B. answered 07/24/19
Tutor
4.7
(31)
Math and computer tutor/teacher
y = 1/(2x) - 3
swaps x and y
x = 1/(2y) - 3
x+3 = 1/(2y)
2y = 1/(x+3)
y = 1/(2(x+3)) = 1/(2x+6)
Tru H.
asked 07/06/19Patrick B. answered 07/24/19
Math and computer tutor/teacher
y = 1/(2x) - 3
swaps x and y
x = 1/(2y) - 3
x+3 = 1/(2y)
2y = 1/(x+3)
y = 1/(2(x+3)) = 1/(2x+6)
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