Freeman B.

asked • 07/04/19

hOW MANY ML OF 0.1 m hcl WOULD BE REQUIRED TO TITRATE 35 ML OF nAoH TO THE END POINT

HOW MANY ML OF 0.1 m hcl WOULD BE REQUIRED TO TITRATE 35 ML OF 1 m nAoh TO THE END POINT

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Lauren H. answered • 07/04/19

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vc = vc

v(.1 mol/L) = (.035L)(1 mol/L)

v = .035 mol/(.1 mol/L)

v = .35 L of .1 M HCl to titrate .035 L of NaOH

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J.R. S.

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Freeman...you can also do this as described without changing mls to liters. (X mls)(0.1 M) = (35 mls)(1 M) and x= 350 mls which is the same as 0.35 L calculated by Lauren H
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07/04/19

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