How many molecules (not moles) of NH3 are produced from 1.00×10−4 g of H2? Express your answer numerically as the number of molecules.

Answer 1

First, balance the Equation

N2 + 3H2 ==> 2 NH3

So, 3 moles of H2 produce 2 moles of NH3

One mole of H2 = 2.016 g.. So, 1.00 * 10^-4 grams yields (1.00*10^-4)/2.016 = 0.496 * 10^-4 Moles of H2.

Using the mole ratio, that yields 0.033 * 10^-4 moles of NH3. Since a mole of anything contain

6.022x10^23 molecules, multiplying moles of NH3 by Avogadro's number yields the answer.

==> 1.99*10^19 molecules.