
Sidney P. answered 07/05/19
Astronomy, Physics, Chemistry, and Math Tutor
For this large shift in wavelength, the usual approximation v/c = (delta lambda)/lambda is not good enough. The valid equation is in terms of frequency f: f/fo = 1 - v/c = lambdao/lambda, where the subscript "o" refers to rest or normal frequency or wavelength. In this case, with slight rearranging, v/c = 1 - 400/520 = 0.2308. With c = 299,800 km/s, the velocity of the star is about 69,200 km/s away from the observer.