then, t = (-.2)ln(1 - .6C_{o}/C_{o}) = (-.2)ln(1-.6) = .183 hours

Caitlin B.

asked • 06/18/19# Exponential and Logarithmic Functions

The rate at which a battery charges is slower the closer the battery is to its maximum charge *C*_{0}. The time (in hours) required to charge a fully discharged battery to a charge *C* is given by

t = -k ln (1-C/C0)

where *k* is a positive constant that depends on the battery. For a certain battery, *k* = 0.2. If this battery is fully discharged, how long will it take to charge to 60% of its maximum charge *C*_{0}? (Round your answer to three decimal places.)

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Caitlin B.

Thank you so much!06/19/19