Stoichiometry question

Question

how many grams of H2 are needed to react with 3.00 g of N2?

balanced equation is N2 + 3H2 -> 2NH3

Answer 1

3 grams of N2×(1 mol N2/28.02gmN2) (3 mol H2/1mol N2) (2.016gm H2/1 mol H2)=

Ans.=0.648g

Answer 2

3.00 g N₂ x (1 mol N₂/28 g N₂) x (3 mol H₂/1 mol N₂) x (2 g H₂/1 mol H₂) =

0.643 g H₂