What is the acceleration of the rocket?

Question

A rocket is fired upwards, starting at rest, and accelerating at a constant rate. During the 15th 1 second interval, the rocket travels 600 meters. What is the acceleration of the rocket?

Please show your work for each step and explain along the way. Thanks!

Answer 1

Kinematic expression for distance traveled at constant acceleration y= y_o + v_ot +1/2 at²

starting at rest y_o and v_o are zero

and t = 0 seconds elapsed

We also have the distance traveled in the 15th 1 second interval being 600 meters

The first 1 second interval is from t=0 to t=1 sec

The second 1 second interval is from t =1 sec to t=2 seconds....

The fifteenth 1 second time interval is from t = 14 seconds to t = 15 seconds....

2(600 m)/(15sec²-14sec²) is our acceleration