Jesse E. answered 06/05/19
Masters in Chemistry and Bachelors in Biology
The balanced combustion reaction for propane is as follows:
C3H8 + 5 O2 ⇔ 3 CO2 + 4 H2O
For a plan, we will use the following:
mol C3H8 → 4 mol H2O/1 mol C3H8 → g H2O/mol H2O → g H2O
4 mol C3H8 → 4 mol H2O/1 mol C3H8 → 18 g H2O/1 mol H2O → 288 g H2O
Therefore, there will be 288 grams H2O produced if 4 mol of propane are burned.