
Matthew C. answered 06/05/19
Bachelor's of Science in Chemistry
Q = mcΔT
ΔT = Q/mc
ΔT = (82 J)/(17 g x 0.128 J/g*oC)
ΔT = 37.68 oC (without two significant figures)
ΔT = 38 oC (with two significant figures)
Ayushi P.
asked 06/05/19If 82 J of heat are added to a pure gold coin with a mass of 17 g , what is its temperature change? Specific heat capacity of gold is 0.128 J/g∘C.
Express your answer using two significant figures.
Matthew C. answered 06/05/19
Bachelor's of Science in Chemistry
Q = mcΔT
ΔT = Q/mc
ΔT = (82 J)/(17 g x 0.128 J/g*oC)
ΔT = 37.68 oC (without two significant figures)
ΔT = 38 oC (with two significant figures)
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