You are lookin good on the first 2!
For the third one, just remember that V in this case is just (.5)Vo
So .5Vo = Vo(1-.075)t or .5 = (.925)t Then log(.5) = t(log(.925))
t = log(.5)/log(.925) = 8.89 years
Mark J.
06/05/19
John D.
Thanks. Actually, as soon as the algebra simplifies to 0.5 = (0.925)^t, it's obvious from the 5 answer choices which is the correct answer (doesn't mean I "get" logs but . . .)06/05/19
Mark J.
06/05/19
John D.
Thanks! I follow the algebra of the 3rd answer until you insert the two logs . . . that I don't get06/05/19