How many mL of 0.100 M NaOH are needed to titrate 20.0 mL of 0.300 M HNO3

Question

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Answer 1

Balanced chemical reaction: HNO₃ (aq) + NaOH (aq) → NaNO₃ (aq) + H₂O (l)

First use the volume and molarity of HNO₃ to calculate the # of moles.

20.0 mL x (1 L / 1000 mL) = 0.0200 L

mol HNO₃ = Molarity x L = 0.300 mol/L x 0.0200 L = 0.00600 mol HNO₃

According to the chemical reaction, 1 mol of HNO₃ reacts with 1 mol of NaOH

mol NaOH = 0.00600 mol HNO₃ x (1 mol NaOH / 1 mol HNO₃) = 0.00600 mol NaOH

Using Molarity of NaOH and the # of moles, calculate the volume first in Liters.

L = mol / Molarity = 0.00600 / 0.100 = 0.0600 L

Volume in mL = 0.0600 L x (1000 mL / 1 L) = 60.0 mL NaOH