
Matthew C. answered 05/31/19
Bachelor's of Science in Chemistry
a. (3.54 x 107 g TiCl4) x (1 mol TiCl4/189.679 g TiCl4) x (1 mol Ti/1 mol TiCl4) x (47.867 g Ti/1 mol Ti) =
8.93 x 106 g Ti
b. Percent Yield = (Actual Yield/Theoretical Yield) x 100%
Percent Yield = ((7.91 x 106 g Ti)/(8.93 x 106 g Ti)) x 100%
Percent Yield = 88.6%

Matthew C.
Ah, no, it should be 3 in this case. So the answer is 88.6%.05/31/19
Elliot C.
Is the percent yield rounded to the sig digs?05/31/19