chemistry question

Question

Consider the following reaction: iron (s) + chlorine (g) à iron (III) chloride a. Write the balanced chemical equation. b. 25.0 g of iron reacts with excess chlorine gas. a. Calculate the moles of iron reactant. b. Calculate the moles of iron (III) chloride. c. Calculate the mass of iron (III) chloride.

Answer 1

Iron reacts with chlorine to form iron+++ Cl₃ according to the following balanced equation:

2Fe + 3Cl₂ → 2FeCl₃

25 grams of iron is 25/55.84 moles of iron = 0.448 moles. According to the above balanced equation, 2 moles of iron produce 2 moles of Ferric Chloride, a 1 : 1 ratio. Therefore, the 0.448 moles of iron will react with chlorine to produce 0.448 moles of iron+++ chloride. The formula weight of FeCl₃ is 55.84 + 3 x 35.45 = 162.19. Since 0.448 moles of product were formed, the mass of the product is 0.448 moles x 162.19 grams/mole = 72.66 grams.