One number exceeds another by 24. The sum of the numbers is 58. What are the numbers?

Question

simple word problem. just seeing if this is legit.

Answer 1

Another approach: Since the sum is 58, the average is 29, since they differ by 24, one number is 12 more than 29, while the other is 12 less than 29, thus, 41 and 17 are the two numbers.

 

Answer 2

Let x be the first number.  The second number exceeds the first number by 24, so it's x+24.  The sum of the two numbers is 58:

 

x + (x + 24) = 58

 

2x = 34

 

Solve for x.

Answer 3

From the question we know that there will be two numbers. 

Lets say the 1st number = x and the 2nd number = y

 

Now we know that one number exceeds from another by 24 so we can write it as:

 

x+24 = y               ....... (1)

 

We also know that the sum of the two numbers is 58, so we we can write it as:

 

x+y = 58               ....... (2)

 

By using the substitution method we can substitute the value of y, from equation (1) into equation (2) and our result will be:

 

x+y =58                    ........... replace the y with (x+24)

 

x+(x+24) =58            ........... Simplify

 

2x+24 =58

 

2x=34

 

x=17

 

Now we have our value for x, so we can plug into any equation (equation (1) or (2)) and get the value of y.  

 

Let's pick equation (2) you can also pick equation (1) both will work.

 

x+y =58                .............. replace the x with 17

 

17 + y = 58           ............... Solve for y

 

y = 58 - 17

 

y= 41

 

You we have the value of x and y which means one number is 17 and the other is 41. 

You can now check if these numbers satisfy the statement in the question.

 

** In the below answer only 1 number is found, where the question says to find both numbers. Which makes the below answer wrong **