
Ellen E. answered 05/28/19
Chemistry Tutor - High School, AP, College
Always, Always, ALWAYS check if the reaction is balanced:
Ca(OH)2 (aq) + H2SO4 (aq) à CaSO4 (aq) + H2O (l)
This one is not quite!
Balance it first:
Ca(OH)2 (aq) + H2SO4 (aq) à CaSO4 (aq) + 2H2O (l)
That’s it for balancing.
Now the question of limiting reagent….
I always just ask myself how much product I could theoretically produce from each amount reactant. The smaller number is the LIMITING reagent.
It’s like, if I have a recipe that calls for 2 cups flour and 6 eggs. I look in my kitchen and I have 4 cups flour and 4 dozen eggs. I have enough flour to make the recipe 2 times. I have enough eggs to make the recipe (48 / 6) 8 times. I’m LIMITED by the flour. Even though I have enough eggs to make the recipe 8 times, In only have enough flour to make it 2 times.
SO, in this case, we’re given a certain amount of calcium hydroxide and a certain amount of sulfuric acid:
78 g Ca(OH)2 x (1 mol / 74.10 g Ca(OH)2] x [2 mol H2O/1 mol Ca(OH)2] = 2.105 mol H2O
100 g H2SO4 x (1 mol / 98.08 g H2SO4] x [2 mol H2O/1 mol H2SO4] = 2.039 mol H2O
This is a close race, but you can make slightly LESS H2O based on the amount of H2SO4 present than you can based on the amount of Ca(OH)2 present. That is, there is enough Ca(OH)2 to make 2.1 moles of H2O, but there is only enough H2SO4 to make 2.04 moles of H2O.
Therefore the yield is LIMITED by the H2SO4. H2SO4 is the limiting reagent.
We will calculate the theoretical yield based on the LIMITING REAGENT:
Theoretically, we can make 2.039 mol H2O, which is (2.039 * 18.00 g/mol) 36.7 grams H2O.
I don’t know if your teacher is a stickler for significant figures, but we technically have only 1 significant figure, and the answer would be 40 grams H2O.
Furthermore, the problem tells us you were only able to recover 34 grams of H2O.
The percent yield is (ACTUAL YIELD/THEORETICAL YIELD) * 100
SO (34/36.7)*100 = 92.6%;
With only one significant figure, you would technically have to say 90% yield.
Shubhi S.
If calcium hydroxide was in limited quantity , then whether we have to check which is limiting reagent or not ?11/06/20