Inactive Tutor answered 05/30/19
a) 1.50 mol NaOH x (1 mol H2SO4 / 2 mol NaOH) x (98 g H2SO4 / 1 mol H2SO4) = 73.5 g H2SO4
b) 60.0 g H2SO4 x (1 mol H2SO4 / 98 g H2SO4) x (2 mol H2O / 1 mol H2SO4) x (18 g H2O / 1 mol H2O) = 22.0 g H2O
Suha A.
asked 05/25/19H2SO4 + 2NaOH -> Na2SO4 + 2H2O
a) what mass of H2SO4 would be required to react with 1.50 moles of NaHO
b) if 60.0g of H2SO4 reacts with sodium hydroxide, what mass of water is produced
Inactive Tutor answered 05/30/19
a) 1.50 mol NaOH x (1 mol H2SO4 / 2 mol NaOH) x (98 g H2SO4 / 1 mol H2SO4) = 73.5 g H2SO4
b) 60.0 g H2SO4 x (1 mol H2SO4 / 98 g H2SO4) x (2 mol H2O / 1 mol H2SO4) x (18 g H2O / 1 mol H2O) = 22.0 g H2O
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