Hope F.

asked • 05/23/19

How to predict mass of product?

If 250.3 L of hydrogen gas (d=0.0899 g/L) reacts with an excess amount of nitrogen gas, what mass of ammonia would be produced? I’ve gone through all of the assigned reading for this module and

how to calculate this type of problem wasn’t in there.

Anonymous A.

You can get the mass of hydrogen given its volume (250.3 L) and its density (0.0899 g/L). You're told there's an **excess** amount of nitrogen gas. So basically, assume there's so much nitrogen gas that all of your hydrogen will produce ammonia using the excess nitrogen gas. So ask yourself how much nitrogen gas you need to react with 250.3 L * 0.0899 g/L hydrogen has.
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05/23/19

1 Expert Answer

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Matthew C. answered • 05/23/19

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Bachelor's of Science in Chemistry

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Let's first write out the balanced chemical equation:


3H2(g) + N2(g) → 2NH3(g)


Since we know the volume of hydrogen gas and its density, we can ultimately solve for the mass of ammonia with our balanced chemical equation:


250.3 L H2 x (0.0899 g H2/1 L H2) x (1 mol H2/2 g H2) x (2 mol NH3/3 mol H2) x (17 g NH3/1 mol NH3) =


127.51 g NH3

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Hope F.

Thanks!
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05/23/19

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