A campsite is 3/4 mile away. They walk a steady speed of 1 1/8 mph. How many minutes will it take them to get to the campsite?

Question

This is a question on my semester exam review homework. and have asked everyone and it. And no one seems to know how to do this problem.

Answer 1

You are given D=distance, V=Speed(also called velocity), and you are asked for T=time.

The relationship among these 3 variables is:

 

 D(mi) = V(mi/hr) * T(hr).  

 

You have D and V, you need T.  Using algebra to solve for T:

T = D/V   D= 3/4 mi = 0.75 mi   V= 1 1/8 mi/hr = 1.125 mi/hr,  

Therefore: D = 0.75/1.125 = 0.6667 hr = 2/3 hr or 40 min.

 

You can also use just the fractions:  D= 3/4, V= 1 1/8 = 9/8, then

T= (3/4) / (9/8) = (3/4)*(8/9) =  2/3 hr or 40 min