
Philip P. answered 12/13/14
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(AUB')∩B
Apply the Distributive Law for set operations:
(AUB')∩B = A∩B U B'∩B
Now B'∩B = 0 (null), so:
(AUB')∩B = A∩B = {b, c, d}∩{c, e, f, g} = {c}