algebra width and length

Question

the perimeters of a rectangle yard is 14 feet. the length is twice the width. what is the width and length of the yard?

Answer 1

Let's call the width w. That makes the length equal to 2w.

The perimeter to two times the length and two times the width, or

Perimeter = 2(2w) + 2(w)

That equals 4w + 2w or 6 w.

So if the perimeter is 14, we can say that 14 = 6w.

Divide by 6 to get w = 14/6 or 7/3.

The width is 7/3 feet or 2 and 1/3 feet, and the length is twice that or 14/3 or 4 and 2/3.