How many moles of KOH would it take to neutralize 0.50 mol H2SO4?

Question

Please explain the answer fully and please be quick because I'm trying to catch up on work that I missed while I'm recovering from being sick.

Answer 1

To begin we must examine the balanced equation:

2KOH + H₂SO₄ -> 2H₂0 + K₂SO₄

From this, we see that for 2 moles of KOH, you need 1 mole of H2SO4 to form 2 moles H₂0 and 1 mole K₂SO₄. Now we use dimensional analysis to solve for moles of KOH:

0.50 mol H₂SO₄ ( 2 mol KOH/ 1 mol H₂SO₄) = 1 mol KOH

Therefore you will need 1 mole of KOH.