Find the probability ? There are 14 shirts in your closet, five blue, five green, and four red. You randomly select a different shirt each day. You wear a blue shirt on Monday,Tuesday, and Wednesday.

Answer 1

Since these events are independent and there are no chance to repeat each shirt since you wear a different shirt each day the answer will be the probability of each event happening. The first day you have 5 blue shirts of the 14 to choose from so Pr (choosing 1 of 5 blue shirts out of 14 ) = 5/14 . The second day since you have already worn a blue shirt there are only 13 shirts to choose from and 4 are blue so the probability is Pr( choosing 1 of 4 blue shirts out oft 13) = 4/13 . For Wednesday since two blue shirts have been chosen there are 3 blue shirts left out of 12 shirts. The Pr(choosing 1 of 3 blue shirts out of 12 shirts ) =3/12 . So the probabililty of choosing 3 DIFFERENT blue shirts on Monday , Tuesday and Wednesday is the Prob of choosing a new blue shirt on Monday & Tuesday & Wednesday. This is (5/14)*(4/13)*(3/12) = (5/182)

(5/182) is my final answer

Answer 2

Find the probability ? There are 14 shirts in your closet, five blue, five green, and four red. You randomly select a different shirt each day. You wear a blue shirt on Monday,Tuesday, and Wednesday.

If each of the shirts is equally-likely to be selected:

Probability = (number of successes) / (total number of possibilities)

P(Blue on Monday) = 5/14

P(Blue on Monday and Tuesday) = (5/14) * (4/13) [Tuesday is important only if Blue on Monday]

P(Blue on Monday and Tuesday and Wednesday) = (5/14)*4(13)*(3/12) = 0.027