Determine the theoretical yield of kcl of you start with 34.5g of k2co3

Answer 1

You haven't provided the reaction, therefore, I am going to assume that the reaction is:

K₂CO₃ + 2 HCl → 2 KCl + H₂O + CO₂

34.5 g K₂CO₃ x (1 mol K₂CO₃ / 138.21 g K₂CO₃) x (2 mol KCl / 1 mol K₂CO₃) x (74.55 g KCl / 1 mol KCl) = 37.2 g KCl