Ishwar S. answered 05/08/19
University Professor - General and Organic Chemistry
CH3CH2CH2–Cl + NaOH → CH3CH2CH2–OH + NaCl
1-chloropropane is a primary alkyl halide. The hydroxide ion from NaOH is a strong nucleophile. When combined, the hydroxide ion (-OH) bonds to the C1 carbon of 1-chloropropane and at the same time, the chloro group leaves.
In the end, the hydroxide is substituting for the chloro group on 1-chloropropane, therefore, this is a substitution reaction. This gives 1-propanol as the main product and sodium chloride is formed as a by-product.