gen chem question

Question

At what temperature do 0.020080 mol of Ne in a 961.9 mL container exert a pressure of 0.95 atm?

Answer 1

We need to use the ideal gas law.

PV=nRT

Pressure is P, V is volume. n is mols, and T is in Kelvin.

R which is the gas constant will determine what kind of units we use. In this case since we have atm, and mL i will use .0821 mols* K / atm L

Converting mL to L, I plug it into the above equation getting:

(.95)(.9619)=(.020080)(.0821)(T)

Solve for T to get 554.3 K