You don't provide enough information to fully answer the question here but I'll give you a sense of how you solve it. I'm assuming the question says "32 mL of XX molar NaOH(aq) were required to neutralize 25 mL of HCl(aq). What was the molarity of the original HCl solution?" or something to that effect.
So whats going on here? Well what does neutralization tell us? It tells us that the moles of acid and base added are equivalent. We can figure out how many moles of base were present because we know that molarity is moles of solute per liter of solution ( M = mol / L). If we rearrange this we see M * L = moles. We know the molarity and we know 32 mL (0.032 L) were used, so if we multiply those we know the number of moles of NaOH that were used. As stated above this is the same as the number of moles of HCl used (thats what is implied by neutralization). So we know our number of moles if HCl, and we know that number of moles was in 25 mL of solution. As above, M = mol / L, so we just divide the number of moles by 0.025 L we get the molarity.
If you have any further questions or want to review more problems feel free to contact me.
