A Cube of Fe is Heated...

Question

A 38.5 gram cube of Fe (c=0.45 J/g C) is heated from 23 Celsius to 195 Celsius by a burner. How much energy was absorbed by the cube in kJ?

Answer 1

This problem is an example of determining the heat of a substance given mass, specific heat, and a change in temperature. The formula to use is as follows:

q = m * s * (T_f-Ti)

where q is the amount of heat, m is the mass in grams, s is the specific heat of the substance, T_f is the final temperature, and T_i is the initial temperature.

To find the energy (q), we simply substitute the given information:

q = 38.5 g * 0.45 J/g C *(195 C - 23 C) = 2979.9 J = 2.98 kJ