F = kx
F = mg
mg = kx
k = mg / x
Grace J.
asked 05/03/19An ideal spring obeys Hooke’s law: F~ = −k ~x. A mass of m = 0.3 kg hung vertically from this spring stretches the spring 0.2 m. The acceleration of gravity is 9.8 m/s 2 . Calculate the value of the force constant k for the spring.
Answer in units of N/m
F = kx
F = mg
mg = kx
k = mg / x
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