One of the important aspects of optics is the fact that if the image can be projected, it must be real.
If we assume object distance = do, the image distance is therefore 2d0
We get 1/f=1/do+1/2d0
The question did not ask for the image distance but it could be calculated from this.
Also since the image is real it has a positive value in the mirror equation. Using the Magnification equation we get
M=-di/do, As both di and do are positive the magnification is negative which means it is inverted.