If you recall, the first law of thermodynamics
ΔU=Q + W
ΔU is the change in internal energy
Q is the heat added to the system
W is the work done on the system.
From the question you can now set up the equation
900J= Q + 1600 J
Alexiss B.
asked 04/28/19An ideal gas is enclosed in a piston, and 1600 J of work is done on the gas. As this happens, the internal energy of the gas increases by only 900 J.
During this process, how much heat flows into or out of the ideal gas? Enter a positive number to indicate a heat flow into the gas or a negative number to indicate a heat flow out of the gas.
If you recall, the first law of thermodynamics
ΔU=Q + W
ΔU is the change in internal energy
Q is the heat added to the system
W is the work done on the system.
From the question you can now set up the equation
900J= Q + 1600 J
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