On this type of question, first you want to determine the molar mass of the given empirical formula CH
Molar Mass of CH = 12.01 g/mol + 1.01 g/mol = 13.02 g/mol
From there then you can determine the subscript amounts by finding what the ratio "n" is
78.11 g / 13.02 g/mol = 6
Meaning that the molecular formula here is
C6H6