What is the final temperature?

Question

A 372 g aluminum engine part at an initial temperature of 20.41 degrees C absorbs 89.8 kJ of heat. What is the final temperature of the part (c of Al= 0.900 J/g*K)?

Answer 1

Hi Diana,

The equation we need is given by: Q = cmΔt = cm(t₂-t₁). All are given except t₂, so, we rearrange the equation to get

t₂ = Q/cm + t₁ = (89,800J/(0.9J/g.^oC*372g) + 20.41^oC

t₂ = 268.22^oC + 20.41^oC = 288.63^oC is the final temperature.

Answer 2

Diana,

 

The equation you need is Q = cmΔT = cm(T_f - T_o), so T_f = T_o + Q / (cm).

 

T_f = 20.41 ^oC  +  89,800 J / [(0.900 /g^oC)(372g)] ,  since Δ1 ^oK = Δ1 ^oC

T_f = 20.41 ^oC  +  268.22 ^oC  = 288.63 ^oC