when aluminum is heated in oxygen aluminum oxide is formed. What weight of the aluminum oxide can be obtained from 27.4g of aluminum

Question

Please show answer and the work to get the answer , thank you

Answer 1

Since Oxygen is one of the naturally occurring diatomic elements, it comes in pairs of 2 when writing out your equation.

Al + O₂ ----> Al₂O₃

Aluminum oxide is written this way because Aluminum is a cation with a charge of +3, while Oxygen is an anion with a charge of -2. The charges crossover thus making Al₂O₃. Your next step is to balance the equation.

4Al + 3O₂ ----> 2Al₂O₃.

Then you start with the value that's given (27.4g Al)

27.4g Al x 1 mol Al x 2 mol Al₂O₃ x 101.96g Al₂O_{3 =} 51.8g Al₂O₃

26.98g Al 4 mol Al 1 mol Al₂O₃