2C8H18 + 25O2 --> 16CO2 + 18H2O

Question

a.) calculate the molar masses of both octae and carbon dioxide

b.) calculate the amount of CO2 in grams, produced by the combustion of 100 g of octane

Answer 1

A) Octane molar mass C=12.01g, H=1.01g

8(12.01g) + 18(1.01g)=~114.26g

Carbon Dioxide molar mass C=12.01g, O= ~16g

1(12.01) + 2(16) = ~44.01g

B) Since your equation is already balanced, you would have to start with what's given, use molar mass of octane, then a mole to mole ratio of octane to CO2, followed by the molar mass of CO2.

100g C₈H₁₈ x 1 mole C₈H₁₈ x 16 mole CO₂ x 44.01g CO₂ = ~ 308.14g CO₂

114.26g C₈H₁₈ 2 mole C₈H₁₈ 1 mole CO₂