
Aleck V. answered 06/22/19
Tutoring maths and sciences for 15 years!
This is subject to the current temperature of water, as the coefficient changes at its initial temperature.
If the coefficient of volumetric expansion of water is 2.5 x 10^-4 / degrees C, then
dV = V(Coeff)(dT)
dV = volume change
V = volume
dT = temperature change
dV = 20L x (2.5 x 10^-4 / degrees C) x 15C
dV = 4.5 x 10^-2 Lor 0.045 Liter change
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