A chemist wants to dilute 50.0ml of 3.50 M Sulfuric acid to 2.00 M Sulfuric acid. To what volume must it be diluted? How do you get the answer?

Answer 1

The dilution equation is M_iV_i = M_fV_f

M_i = 3.50 M

V_i = 50.0 mL

M_f = 2.00 M

V_f = ?

Rearrange the dilution equation to solve for V_f

V_f = M_iV_i / M_f = (3.50 M x 50.0 mL) / 2.00 M = 87.5 mL