If a gas occupies 3.6L at a pressure of 1.00atm, what will it's volume be at a pressure of 2.5atm

Answer 1

Use Boyle's Law to solve this problem.

P₁V₁ = P₂V₂

P₁ = 1.00 atm

V₁ = 3.6 L

P₂ = 2.5 atm

V₂ = ?

Rearrange the above equation to solve for V₂

V₂ = P₁V₁ / P₂

= (1.00 atm x 3.6 L) / (2.5 atm) = 1.4 L