Your answer to (a) looks good. I can’t see the values for (b) but a positive change in enthalpy seems reasonable.
Part (c) is asking you to think about the change in free energy equation. A reaction is more thermodynamically favorable as the ΔG becomes more negative. The ΔH is positive, which is not a favorable condition, however ΔS is positive, which is favorable. ΔG = ΔH - TΔS, so as temperature increases, the reaction will become more favorable as the ΔG will become more negative.
For part (d), the NO is a gas, so it will leave as it is produced as long as it’s an open container. Given the reactants are used in the given ratio from the equation (and assuming the reaction goes to completion) there should only be silver nitrate and water left at the end, so you could just evaporate the water and be left with just silver nitrate solid.
I hope this helps!