Possible outcomes are win 2 , lose 2 or win 1and lose 1
P( wins first race) = .7 then P( loses first race)= .3
P(wins second race ) =.6 then P(loses second race) = .4
I will answer the part c first. P( loses both races)= .3 x .4 = .12
Part a P he wins at least 1 race would be all other outcomes = 1.00 -.12 = .88
To win just one race he could either win the first and lose the second ( .7 x .4 = .28) or lose the first and win the second ( .3 x .6 = .18 ) which totals to .28 +.18 = .46