Inactive Tutor answered 04/18/19
y' = (32x^3)/(1+x^4)
y'' = (96x^2 - 42x^6)/(1+x^4)^2
y''' contains functions of x whose intercepts are zero; that is they do not contain final constant terms.
therefore the derivatives are zero at x=0.
Erik K.
asked 04/18/19Find a power series representation of f. Use a geometric series and properties of a power series.
(Assume that −1 ≤ x ≤ 1.)
f(x) = 8 ln(1 + x4)
Inactive Tutor answered 04/18/19
y' = (32x^3)/(1+x^4)
y'' = (96x^2 - 42x^6)/(1+x^4)^2
y''' contains functions of x whose intercepts are zero; that is they do not contain final constant terms.
therefore the derivatives are zero at x=0.
Inactive Tutor answered 04/18/19
What is the series for ln(1+x)? No replace x with x^4
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