Kiera G. answered 05/25/19
BA in Computational Mathematics, MS in Applied Mathematics
Often times, it's easier to prove when these are properties are violated.
T1 is not antisymmetric, as (c, b) and (b, c) exist in it. For every other relation, there is no pair (x, y) and (y, x) where x != y. So T2 and T3 are antisymmetric.
I think you're missing a not symbol (¬) in that definition of asymmetric. Asymmetry is the same as antisymmetry except that there's no x != y condition, meaning that a pair (x, x) cannot exist in an asymmetric set. T1 is already eliminated since it is not antisymmetric, but T2 is also eliminated as well since it contains (a, a). T3 does not contain any pairs like that, so it is asymmetric as well as antisymmetric.
Relation | Antisymmetric | Asymmetric |
T1 | x | x |
T2 | v | x |
T3 | v | v |