Peter N. answered 04/12/19
PhD with over 15 years of teaching social science statistics.
p=0.5 (default since no value is given)
q=1-0.5=0.5
margin of error=5%=0.05
z_c=1.65 at 90% confidence.
margin of error: e= sqrt(p(1-p)/n)*z_c
or, 0.05=sqrt(0.5*0.5/n)*1.65
or, n= (0.5*1.65/0.05)^2=272.25
The required sample size=273
Lajonathon T.
What if the margin of error was 7% at a confidence level of 90%, what would it be?12/06/21

Peter N.
12/06/21
Lajonathon T.
how would I plug it in the formula? never seen that equation before.12/06/21

Peter N.
12/06/21
Lajonathon T.
thank you for the explanation!12/06/21
Janelle M.
Can a margin of error be negative?11/10/22
Lajonathon T.
What if the margin of error was 7% at a confidence level of 90%, what would that be?12/06/21