The radiator in a car is filled with a solution of 65% antifreeze and 35%t water. The manufacturer of the antifreeze suggests that for summer driving, optimal cooling of the engine is obtained with only 50% antifreeze. If the capacity of the raditor is 3.6 liters, how much coolant (in liters) must be drained and replaced with pure water to reduce the antifreeze concentration to 50%?
Let x = the amount of coolant to be drained.
Balance by the amount of solute:
(3.6-x)(.65) = 3.6(0.5)
Solve for x,
x = (3.6)(.6)/(.65)=3.323 liters