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Two cyclists, 144 miles apart, start riding toward each other at the same time.

Two cyclists, 144 miles apart, start riding toward each other at the same time. One cycles 3 times as fast as the other. If they meet 4 hours later, what is the speed (in mi/h) of the faster cyclist?

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Kevin S. |
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Let X = the speed of the slower cyclist. Therefore 3X = the speed of the faster cyclist. 

Since Rate * time = Distance

4X + 4 (3X) = 144 miles

Simplify, collect like terms, and solve for X to get the speed of the slower cyclist. Then multiply by 3 to get the speed of the faster cyclist.