Ishwar S. answered 04/07/19
University Professor - General and Organic Chemistry
CdCO3 (s) <==> Cd2+ (aq) + CO32- (aq)
Ksp = [Cd2+] [CO32-] = 5.2 x 10-12
Let x = [Cd2+] = [CO32-]
(x)(x) = 5.2 x 10-12
x2 = 5.2 x 10-12
x = √5.2 x 10-12 = 2.3 x 10-6
Molar solubility = 2.3 x 10-6 M