How many grams of methanol are produced when 2.8 grams of carbon monoxide reacts with 0.50 grams of hydrogen gas?

Question

A. 3.2 grams

B. 3.6 grams

C. 4.0 grams

D. 6.0 grams

Answer 1

Balanced chemical reaction: CO (g) + 2 H₂ (g) → CH₃OH (l)

First use stoichiometry to convert grams of CO and H₂ to moles of CH₃OH to determine which reactant is the limiting reagent.

2.8 g CO x (1 mol CO / 28 g CO) x (1 mol CH₃OH / 1 mol CO) = 0.10 mol CH₃OH

0.50 g H₂ x (1 mol H₂ / 2 g H₂) x (1 mol CH₃OH / 2 mol H₂) = 0.13 mol CH₃OH

As you can see, CO produces less CH₃OH, therefore, it is the limiting reagent. Now convert 0.10 mol CH₃OH to grams CH₃OH.

0.10 mol CH₃OH x (32 g CH₃OH / 1 mol CH₃OH) = 3.2 g CH₃OH (answer choice A)

Answer 2

The first thing you need to do is write the balanced equation. Can you show me that or do you need to learn how to do that first? I will guide you to the answer, but I will not give it to you. You can message me on the website.