the theoretical yield of Cl2 from certain starting amounts of MnO2 and HCl was calculated as 58.95 g and 55.35 g, respectively. if the percentage yield of Cl2 is 75% what is its actual yield?

Question

A. 41.51 g

B. 42.31 g

C. 43.61 g

D. 44.21 g

Answer 1

First compare the theoretical yields from the two reagents. Since the theoretical yield calculated from HCl is lower that what was calculated from MnO2, you know that HCl is the limiting reagent. Since HCl is the limiting reagent, its theoretical yield of 55.35g is the theoretical yield of Cl2 for the reaction.

From there, use the Percentage Yield formula to calculate the Actual Yield:

Percentage Yield = (Actual Yield) / (Theoretical Yield)

75% = (Actual Yield) / 55.35g

Actual Yield = 75% * 55.35g

Actual Yield = 41.51g