Rodrigo M. answered 04/06/19
Chemistry B.Sc.
For part A, you were given the concentration of the hydronium ion which can be used to find the concentration of the hydroxide ion by combining the following equations
Equation 1: pH = -log([H3O+])
Equation 2: pOH = -log([OH-])
Equation 3: pH + pOH = 14
First find pH.
using equation 1, pH = -log(1.57x10^-13) = 12.8
NOTE: The most convenient way to answer part B is to use pH. Since we solved pH to be larger than 7, the solution is basic.
Second find pOH.
rearranging equation 3 gives pOH = 14 - pH = 14 - 12.8 = 1.2
Third find [OH-].
rearranging equation 2 gives [OH-] = 10^(-pOH) = 10^(-1.2) = 6.3x10^-2