How many grams of sodium iodide must be used to produce 43.0 g of iodine?

Question

2NaI + Cl2 ⟶I2 + 2NaCl

So I've been struggling with this question. I wrote out the conversion factor write but every time I enter my the answer I get from my calculator it tells me that I am wrong. Can somebody walk me through this?

Answer 1

2 NaI + Cl₂ --> I₂ + 2NaCl

x g 43.0 g

43.0 g I₂ x 1 mole I₂ x 2 mole NaI x 149.9 g NaI = 50.8 g NaI

253.8 g I₂ 1 mole I₂ 1 mole NaI