Chemistry problem

Question

A scuba diver exhales 2.55 L of air while swimming at a depth of 89.10 m where the sum of atmospheric pressure and water pressure is 9.62 atm. By the time this exhaled air rises to the surface, where the pressure is 1.00 atm, what is its volume?

      L 

answer in Liters

Answer 1

Conspicuously missing from this problem involving pressures, volumes, and gases is any mention of temperature. This means that you have to assume that the temperature just below the surface of the water is equal to the temperature of the water at the diver's depth. Also, it means you can use Boyle's Law!

P₁V₁ = P₂V₂

Solve for V₂.

P₁V₁ / P₂ = V₂

Now, plug in the numbers. Assume that the pressure just beneath the surface is 1 atm.